The phase response of a passband waveform at receiver is given by $\phi \left( f \right) = - 2\pi \alpha \left( {f - {f_c}} \right) - 2\pi \beta {f_c}$Where ${f_c}$ is center frequency and $\alpha ,\beta $ are positive constants. The actual signal propagation delay from transmitter to receiver is:

Question

The phase response of a passband waveform at receiver is given by $\phi \left( f \right) = - 2\pi \alpha \left( {f - {f_c}} \right) - 2\pi \beta {f_c}$Where ${f_c}$ is center frequency and $\alpha ,\beta $ are positive constants. The actual signal propagation delay from transmitter to receiver is:

TuteeHUB · Accepted Answer

$\beta$

TuteeHUB · Answer

$\frac{{\alpha - \beta }}{{\alpha + \beta }}$

TuteeHUB · Answer

$\frac{{\alpha \beta }}{{\alpha + \beta }}$

TuteeHUB · Answer

$\alpha $

1.	The phase response of a passband waveform at receiver is given by \(\phi \left( f \right) = - 2\pi \alpha \left( {f - {f_c}} \right) - 2\pi \beta {f_c}\)Where \({f_c}\) is center frequency and \(\alpha ,\beta \) are positive constants. The actual signal propagation delay from transmitter to receiver is:
A.	\(\frac{{\alpha - \beta }}{{\alpha + \beta }}\)
B.	\(\frac{{\alpha \beta }}{{\alpha + \beta }}\)
C.	\(\alpha \)
D.	\(\beta\)
Answer» D. \(\beta\)

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