MCQOPTIONS
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| 1. |
The one-dimensional Poisson equation for the surface space charge region at the drain is |
| A. | \(\frac{{{\partial ^2}{\rm{\Psi }}}}{{\partial \;{x^2}}} = - \frac{q}{{{\varepsilon _s}}}\left( {N_D^ + + N_A^ - } \right)\) |
| B. | \(\frac{{{\partial ^2}{\rm{\Psi }}}}{{\partial {x^2}}} = \frac{{ - q}}{{{\epsilon_S}}}\left( {N_D^ + + N_A^ - + p + n} \right)\) |
| C. | \(\frac{{{\partial ^2}{\rm{\Psi }}}}{{\partial {x^2}}} = \frac{{ - q}}{{{\epsilon_S}}}\left( {N_D^ + - N_A^ - + p - n} \right)$\) |
| D. | \(\frac{{{\partial ^2}{\rm{\Psi }}}}{{\partial {x^2}}} = \frac{{ - q}}{{{\epsilon_S}}}\left( {p - n} \right)\) |
| Answer» D. \(\frac{{{\partial ^2}{\rm{\Psi }}}}{{\partial {x^2}}} = \frac{{ - q}}{{{\epsilon_S}}}\left( {p - n} \right)\) | |