1.

The London equation in a super conductor is:

A. \(\nabla^2 B=B(mc^2)/(4\pi \ nq^2)\)
B. \(\nabla^2 B=B(mc^2)/(4\pi \ nq^2)^{1/2}\)
C. \(\nabla^2 B=B(mc^2)/(4\pi \ nq^2)^2\)
D. \(\Delta B = B(mc^2)/(4\pi nq^2)\)
Answer» B. \(\nabla^2 B=B(mc^2)/(4\pi \ nq^2)^{1/2}\)


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