1.

The general solution of the differential equation 9yy’ + 4x = 0 is, \(\left( {{\rm{y'}} = \frac{{{\rm{dy}}}}{{{\rm{dx}}}},{\rm{\;C}} = {\rm{constant}}} \right)\)

A. 9x2 + 4y2 = C
B. \(\frac{{{{\rm{x}}^2}}}{9} - \frac{{{{\rm{y}}^2}}}{4} = {\rm{C}}\)
C. 4x2 + 9y2 = C
D. \(\frac{{{{\rm{x}}^2}}}{4} - \frac{{{{\rm{y}}^2}}}{9} = {\rm{C}}\)
Answer» D. \(\frac{{{{\rm{x}}^2}}}{4} - \frac{{{{\rm{y}}^2}}}{9} = {\rm{C}}\)


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