MCQOPTIONS
Saved Bookmarks
| 1. |
The general solution of the differential equation 9yy’ + 4x = 0 is, \(\left( {{\rm{y'}} = \frac{{{\rm{dy}}}}{{{\rm{dx}}}},{\rm{\;C}} = {\rm{constant}}} \right)\) |
| A. | 9x2 + 4y2 = C |
| B. | \(\frac{{{{\rm{x}}^2}}}{9} - \frac{{{{\rm{y}}^2}}}{4} = {\rm{C}}\) |
| C. | 4x2 + 9y2 = C |
| D. | \(\frac{{{{\rm{x}}^2}}}{4} - \frac{{{{\rm{y}}^2}}}{9} = {\rm{C}}\) |
| Answer» D. \(\frac{{{{\rm{x}}^2}}}{4} - \frac{{{{\rm{y}}^2}}}{9} = {\rm{C}}\) | |