MCQOPTIONS
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| 1. |
The general solution of \(\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}} - 1 = 0\) is |
| A. | \({\rm{y}} = {{\rm{c}}_1}{{\rm{e}}^{\rm{x}}} + {{\rm{c}}_2}{{\rm{e}}^{ - {\rm{x}}}}\) |
| B. | \({\rm{y}} = {{\rm{c}}_1}\cos {\rm{x}} + {{\rm{c}}_2}\sin {\rm{x}}\) |
| C. | \({\rm{y}} = {{\rm{c}}_1}{\rm{x}} + {{\rm{c}}_2} + \frac{{{{\rm{x}}^2}}}{2}\) |
| D. | \({\rm{y}} = {{\rm{c}}_1}{{\rm{e}}^{\rm{x}}} + {{\rm{c}}_2}\cos {\rm{x}}\) |
| Answer» D. \({\rm{y}} = {{\rm{c}}_1}{{\rm{e}}^{\rm{x}}} + {{\rm{c}}_2}\cos {\rm{x}}\) | |