MCQOPTIONS
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| 1. |
The general solution of \(\frac{{dx}}{{{y^2}}} = \frac{{dy}}{{{x^2}}} = \frac{{dz}}{{{x^2}{y^2}{z^2}}}\) will be: |
| A. | x + 3y = C1Y2 + z3 = C2, where C1 and C2 are arbitrary constants. |
| B. | x3 + y2 = C1, x2 + 3z2 = C2, where C1 and C2 are arbitrary constants. |
| C. | x3 - y3 = C1, x3 + 3z-1 = C2, where C1 and C2 are arbitrary constants. |
| D. | x2 + 2y2 = C1, x3 - 3z = C2, where C1 and C2 are arbitrary constants. |
| Answer» D. x2 + 2y2 = C1, x3 - 3z = C2, where C1 and C2 are arbitrary constants. | |