MCQOPTIONS
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| 1. |
The Fourier sin transform of xm-1 is defined by |
| A. | \(\mathop \smallint \limits_0^\infty {x^{m - 1}}\sin sx\) |
| B. | \(\mathop \smallint \limits_{ - \infty }^\infty {x^{m - 1}}\sin sx\) |
| C. | \(\mathop \smallint \limits_0^\infty {x^{m - 1}}\sin x\) |
| D. | \(\mathop \smallint \limits_{ - \infty }^\infty {x^{m - 1}}\sin x\) |
| Answer» C. \(\mathop \smallint \limits_0^\infty {x^{m - 1}}\sin x\) | |