The equation \[\frac{(x+2)(x-5)}{(x-3)(x+6)}=\frac{x-2}{x+4}\] has

1.	The equation \[\frac{(x+2)(x-5)}{(x-3)(x+6)}=\frac{x-2}{x+4}\] has
A.	3 roots
B.	2 roots
C.	1 root
D.	no root
Answer» D. no root

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