If \[x+\frac{1}{x}=5\] (where\[x\ne 0\]) then find \[\frac{2x}{3{{x}^{2}}-5x+3}=?\]

If \[x+\frac{1}{x}=5\] (where\[x\ne 0\]) then find \[\frac{2x}{3{{x}^{

1.	If \[x+\frac{1}{x}=5\] (where\[x\ne 0\]) then find \[\frac{2x}{3{{x}^{2}}-5x+3}=?\]
A.	\[\frac{1}{2}\]
B.	\[\frac{1}{3}\]
C.	\[\frac{1}{4}\]
D.	\[\frac{1}{5}\]
Answer» E.

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If \[x+\frac{1}{x}=5\] (where\[x\ne 0\]) then find \[\frac{2x}{3{{x}^{2}}-5x+3}=?\]

If \[x+\frac{1}{x}=5\] (where\[x\ne 0\]) then find \[\frac{2x}{3{{x}^{2}}-5x+3}=?\]

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