1.

The DTFT of x[n] = 0.5n u[n] using geometric series is:

A. \(X\left( \omega \right) = \frac{1}{{1 - 0.5{e^{ - j\omega }}}}\)
B. X(ω)=1 – 0.5ejω
C. X(ω)=1 – 0.5e-jω
D. \(X\left( \omega \right) = \frac{1}{{1 - 0.5{e^{j\omega }}}}\)
Answer» B. X(ω)=1 – 0.5ejω


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