MCQOPTIONS
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| 1. |
The DTFT of x[n] = 0.5n u[n] using geometric series is: |
| A. | \(X\left( \omega \right) = \frac{1}{{1 - 0.5{e^{ - j\omega }}}}\) |
| B. | X(ω)=1 – 0.5ejω |
| C. | X(ω)=1 – 0.5e-jω |
| D. | \(X\left( \omega \right) = \frac{1}{{1 - 0.5{e^{j\omega }}}}\) |
| Answer» B. X(ω)=1 – 0.5ejω | |