MCQOPTIONS
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| 1. |
The differential equation \(\frac{{dy}}{{dx}} + 4y = 5\) is valid in the domain 0 ≤ x ≤ 1 with y (0) = 2.25 The solution of the differential equation is |
| A. | y = e-4x + 5 |
| B. | y = e-4x + 1.25 |
| C. | y= e4x + 5 |
| D. | y= e4x + 1.25 |
| Answer» C. y= e4x + 5 | |