The current in a circuit with 10 Ω resistance is i = 3 + 4 sin (100 t + 45°) + 4 sin (300 t + 60°) A. The rms current and power dissipated are

The current in a circuit with 10 Ω resistance is i = 3 + 4 sin (100 t

1.	The current in a circuit with 10 Ω resistance is i = 3 + 4 sin (100 t + 45°) + 4 sin (300 t + 60°) A. The rms current and power dissipated are
A.	√41 A and 410 W
B.	√35 A and 350 W
C.	5 A and 250 W
D.	11 A and 1210 W
Answer» D. 11 A and 1210 W