1.

The current i(t) through a 10 Ω resistor in series with an inductance is given by i(t) = 3 + 4 sin (100t + 45°) + 4 sin (300t + 60°) Amperes. The RMS value of the current and the power dissipated in the circuit are

A. 41 A, 410 W respectively
B. 35 A, 350 W respectively
C. 5 A, 250 W respectively
D. 11 A, 1210 W respectively
Answer» D. 11 A, 1210 W respectively


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