The current density in a medium is given by\({\rm{\vec J}} = \frac{{400{\rm{sin\theta }}}}{{2{\rm{\pi }}\left( {{{\rm{r}}^2} + 4} \right)}}{{\rm{\hat a}}_{\rm{r}}}{\rm{A}}{{\rm{m}}^{ - 2}}\)The total current and the average current density flowing through the portion of a spherical surface \({\rm{r}} = 0.8{\rm{\;m}},\frac{{\rm{\pi }}}{{12}}{\rm{\;}} \le {\rm{\;\theta \;}} \le \frac{{\rm{\pi }}}{4},{\rm{\;}}0{\rm{\;}} \le {\rm{\;}}\phi {\rm{\;}} \le {\rm{\;}}2{\rm{\pi }}\) are given, respectively, by

The current density in a medium is given by\({\rm{\vec J}} = \frac{{40

1.	The current density in a medium is given by\({\rm{\vec J}} = \frac{{400{\rm{sin\theta }}}}{{2{\rm{\pi }}\left( {{{\rm{r}}^2} + 4} \right)}}{{\rm{\hat a}}_{\rm{r}}}{\rm{A}}{{\rm{m}}^{ - 2}}\)The total current and the average current density flowing through the portion of a spherical surface \({\rm{r}} = 0.8{\rm{\;m}},\frac{{\rm{\pi }}}{{12}}{\rm{\;}} \le {\rm{\;\theta \;}} \le \frac{{\rm{\pi }}}{4},{\rm{\;}}0{\rm{\;}} \le {\rm{\;}}\phi {\rm{\;}} \le {\rm{\;}}2{\rm{\pi }}\) are given, respectively, by
A.	7.55 A, 7.25 Am-2
B.	18.73 A, 13.65 Am-2
C.	12.86 A, 9.23 Am-2
D.	10.28 A, 7.56 Am-2
Answer» B. 18.73 A, 13.65 Am-2