The approximate Bode magnitude plot of a minimum-phase system is shown in the figure below. The transfer function of the system is

Question

TuteeHUB · Accepted Answer

${10^7}\frac{{{{\left( {s + 0.1} \right)}^2}}}{{{{\left( {s + 10} \right)}^2}\left( {s + 100} \right)}}$

TuteeHUB · Answer

${10^8}\frac{{{{\left( {s + 0.1} \right)}^2}}}{{{{\left( {s + 10} \right)}^2}\left( {s + 100} \right)}}$

TuteeHUB · Answer

${10^7}\frac{{{{\left( {s + 0.1} \right)}^3}}}{{{{\left( {s + 10} \right)}^2}\left( {s + 100} \right)}}$

TuteeHUB · Answer

${10^8}\frac{{{{\left( {s + 0.1} \right)}^3}}}{{{{\left( {s + 10} \right)}^2}\left( {s + 100} \right)}}$

1.	The approximate Bode magnitude plot of a minimum-phase system is shown in the figure below. The transfer function of the system is
A.	\({10^8}\frac{{{{\left( {s + 0.1} \right)}^2}}}{{{{\left( {s + 10} \right)}^2}\left( {s + 100} \right)}}\)
B.	\({10^7}\frac{{{{\left( {s + 0.1} \right)}^3}}}{{{{\left( {s + 10} \right)}^2}\left( {s + 100} \right)}}\)
C.	\({10^8}\frac{{{{\left( {s + 0.1} \right)}^3}}}{{{{\left( {s + 10} \right)}^2}\left( {s + 100} \right)}}\)
D.	\({10^7}\frac{{{{\left( {s + 0.1} \right)}^2}}}{{{{\left( {s + 10} \right)}^2}\left( {s + 100} \right)}}\)
Answer» D. \({10^7}\frac{{{{\left( {s + 0.1} \right)}^2}}}{{{{\left( {s + 10} \right)}^2}\left( {s + 100} \right)}}\)

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