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| 1. |
The angle of elevation of the top of a tower from a point on the ground which is at a distance of 70 m from the foot of the tower is 60° . Then the height of the tower is: |
| A. | \(\frac{70}{\sqrt{3}}\) |
| B. | 80\(\sqrt{3}\) |
| C. | \(\frac{80}{\sqrt{3}}\) |
| D. | 70\(\sqrt{3}\) |
| Answer» E. | |