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1. |
The anchorage length of tension field is |
A. | s = (2 sinφ)(M<sub>fr</sub>/f<sub>yw</sub>t<sub>w</sub>)<sup>0.5</sup> |
B. | s = (2/ sinφ)(M<sub>fr</sub>/f<sub>yw</sub>t<sub>w</sub>) |
C. | s = (2/ sinφ)(M<sub>fr</sub>/f<sub>yw</sub>t<sub>w</sub>)<sup>0.5</sup> |
D. | s = (2/ sinφ)(M<sub>fr</sub>f<sub>yw</sub>t<sub>w</sub>) |
Answer» D. s = (2/ sin‚âà√¨‚àö√∫)(M<sub>fr</sub>f<sub>yw</sub>t<sub>w</sub>) | |