MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
This section includes 39 Mcqs, each offering curated multiple-choice questions to sharpen your Design Steel Structures knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Virtual work is used to determine _____ |
| A. | yield load |
| B. | elastic load |
| C. | plastic load |
| D. | collapse load |
| Answer» E. | |
| 2. |
Principle of virtual work is used to satisfy _____ |
| A. | mechanism condition |
| B. | equilibrium condition |
| C. | plasticity condition |
| D. | no condition is satisfied |
| Answer» C. plasticity condition | |
| 3. |
Which load is obtained when equilibrium and plasticity conditions of plastic analysis are satisfied? |
| A. | plastic limit load |
| B. | upper bound solution of true ultimate load |
| C. | lower bound solution of true ultimate load |
| D. | no solution |
| Answer» D. no solution | |
| 4. |
For a fixed beam with a concentrated load w at \(\frac{1}{4}\) of span from one end, the ultimate load is |
| A. | \(\frac{{16{M_p}}}{{3L}}\) |
| B. | \(\frac{{4{M_p}}}{L}\) |
| C. | \(\frac{{32{M_p}}}{{3L}}\) |
| D. | \(\frac{{6{M_p}}}{L}\) |
| Answer» D. \(\frac{{6{M_p}}}{L}\) | |
| 5. |
According to IS 800, while using plastic method of analysis, unless adequate ductility and plastic rotation capacity are established for design loading conditions, the yield stress of the grade of the steel used shall not exceed |
| A. | 415 MPa |
| B. | 500 MPa |
| C. | 550 MPa |
| D. | 450 MPa |
| E. | 380 MPa |
| Answer» E. 380 MPa | |
| 6. |
A prismatic beam (as shown below) has plastic moment capacity of MP, then the collapse load P of the beam is |
| A. | \(\frac{{2{{\rm{M}}_{\rm{P}}}}}{{\rm{L}}}\) |
| B. | \(\frac{{4{{\rm{M}}_{\rm{P}}}}}{{\rm{L}}}\) |
| C. | \(\frac{{6{{\rm{M}}_{\rm{P}}}}}{{\rm{L}}}\) |
| D. | \(\frac{{8{{\rm{M}}_{\rm{P}}}}}{{\rm{L}}}\) |
| Answer» D. \(\frac{{8{{\rm{M}}_{\rm{P}}}}}{{\rm{L}}}\) | |
| 7. |
Propped cantilever ABCD is loaded as shown in figure. If it is of uniform cross-section, the collapse load of the beam will be nearly |
| A. | \(6.5\frac{{{M_p}}}{L}\) |
| B. | \(5.6\frac{{{M_p}}}{L}\) |
| C. | \(4.7\frac{{{M_p}}}{L}\) |
| D. | \(3.8\frac{{{M_p}}}{L}\) |
| Answer» B. \(5.6\frac{{{M_p}}}{L}\) | |
| 8. |
A simply supported steel beam of rectangular section and of span L is subjected to a uniformly distributed load. The length of the plastic hinge by considering moment ration of 1.5 will be nearly |
| A. | 0.27 L |
| B. | 0.39 L |
| C. | 0.45 L |
| D. | 0.58 L |
| Answer» E. | |
| 9. |
In the plastic theory used for steel, which of the following assumptions are not applicable |
| A. | Steel is ductile and can undergo deformation without rupturing |
| B. | Elastic deformation is taken into account |
| C. | All connections provide satisfactory continuity so as to transmit the plastic moment |
| D. | Steel is assumed to be an ideal elastic-plastic material |
| E. | Plane sections before bending remain plain after bending |
| Answer» C. All connections provide satisfactory continuity so as to transmit the plastic moment | |
| 10. |
If the shape factor of a section is 1.5 and the factor of safety to be adopted in 2, then the load factor will be |
| A. | 0.75 |
| B. | 1.5 |
| C. | 2.5 |
| D. | 3 |
| Answer» E. | |
| 11. |
Load factor in plastic design depends upon |
| A. | nature of loading |
| B. | support conditions |
| C. | geometrical shape |
| D. | All of the above |
| Answer» E. | |
| 12. |
If only a beam mechanism is possible in the frame given below, what will be the plastic Moment Mp developed? |
| A. | 10 kNm |
| B. | 20 kNm |
| C. | 40 kNm |
| D. | 80 kNm |
| Answer» C. 40 kNm | |
| 13. |
Calculate the plastic section modulus of a beam which is experiencing a maximum bending moment of 590.63 KN-m (take partial safety factor as 1.10 and yield strength of steel as 250 N/mm2) |
| A. | 2246.64 cm3 |
| B. | 1568.16 cm3 |
| C. | 1856.15 cm3 |
| D. | 2598.77 cm3 |
| Answer» E. | |
| 14. |
If only a sway mechanism is possible in the frame given below, what will be the plastic moment Mp developed? |
| A. | 10 kNm |
| B. | 20 kNm |
| C. | 40 kNm |
| D. | 80 kNm |
| Answer» D. 80 kNm | |
| 15. |
A prismatic steel beam is shown in the figure.The plastic moment, Mp calculated for the collapse mechanism using static method and kinematic method is |
| A. | Mp,static <\(\frac{2PL}{9}\) =Mp,kinematic |
| B. | Mp,static <\(\frac{2PL}{9}\) ≠ Mp,kinematic |
| C. | Mp,static = \(\frac{2PL}{9}\) = Mp,kinematic |
| D. | Mp,static > \(\frac{2PL}{9}\) = Mp,kinematic |
| Answer» D. Mp,static > \(\frac{2PL}{9}\) = Mp,kinematic | |
| 16. |
A propped cantilever beam of span l and constant plastic moment capacity Mp carries a concentrated load at mid-span. The load at collapse will be |
| A. | \(\frac{{2\;{M_p}}}{l}\) |
| B. | \(\frac{{4\;{M_p}}}{l}\) |
| C. | \(\frac{{6\;{M_p}}}{l}\) |
| D. | \(\frac{{8\;{M_p}}}{l}\) |
| Answer» D. \(\frac{{8\;{M_p}}}{l}\) | |
| 17. |
For portal frame shown in the figure, collapse load W has been calculated as per combined mechanism as \(W = \frac{{16{M_p}}}{{3l}}\)What is the bending moment at B at collapse conditions? |
| A. | \(\frac{{Wl}}{{16}}\) |
| B. | \(\frac{{Wl}}{8}\) |
| C. | \(\frac{{3Wl}}{{16}}\) |
| D. | \(\frac{{3Wl}}{8}\) |
| Answer» D. \(\frac{{3Wl}}{8}\) | |
| 18. |
A rectangular beam of depth d is under bending. Load has been gradually increased when the top fibre has obtained five times the strain at the first yield. What depth of the beam will still respond by elastic conditions? |
| A. | 0.16 d |
| B. | 0.20 d |
| C. | 0.25 d |
| D. | 0.40 d |
| Answer» C. 0.25 d | |
| 19. |
Match the information given in Group – I with those in Group - II. Group I Group IIPFactor to decrease ultimate strength to design strength1Upper bound on ultimate loadQFactor to increase working load to ultimate load for design2Lower bound on ultimate loadRStatic method of ultimate load analysis3Material partial safety factorSKinematical mechanism method of ultimate load analysis4Load factor |
| A. | P - 1; Q - 2; R - 3; S - 4 |
| B. | P - 2; Q - 1; R - 4; S - 3 |
| C. | P - 3; Q - 4; R - 2; S - 1 |
| D. | P - 4; Q - 3; R - 2; S - 1 |
| Answer» D. P - 4; Q - 3; R - 2; S - 1 | |
| 20. |
Consider a triangular section with base b and height h as shown in the figure.The shape factor will be nearly |
| A. | 2.3 |
| B. | 3.2 |
| C. | 4.1 |
| D. | 5 |
| Answer» B. 3.2 | |
| 21. |
For a simply supported steel beam of span L and carrying a point load at the mid-length, at the stage of collapse, what part of the beam is fully elastic |
| A. | L/3 from each end |
| B. | L/4 from each end |
| C. | L/5 from each end |
| D. | L/6 from each end |
| E. | No part of the beam remains elastic at collapse |
| Answer» B. L/4 from each end | |
| 22. |
In considering Plastic Analysis, which of the following is a valid comprehensive statement? |
| A. | Shape factor is the ratio of Plastic Section Modulus to the Elastic Section Modulus |
| B. | Shape factor is the ratio of Elastic Section Modulus to the Plastic Section Modulus |
| C. | Shape factor is the ratio of Plastic Section Modulus to the Elastic section Modulus and its value is always greater than 1.0 |
| D. | Shape factor is the ratio of Elastic Section Modulus to the Plastic Section Modulus and its value is always less than 1.0 |
| Answer» D. Shape factor is the ratio of Elastic Section Modulus to the Plastic Section Modulus and its value is always less than 1.0 | |
| 23. |
A fixed end beam is subjected to a load, W at 1/3rd span from the left support as shown in the figure. The collapse load of the beam is: |
| A. | 16.5 MP/L |
| B. | 15.5 MP/L |
| C. | 15.0 MP/L |
| D. | 16.0 MP/L |
| Answer» D. 16.0 MP/L | |
| 24. |
A propped cantilever beam shown in the figure has a plastic moment capacity of M0The collapse load is |
| A. | \(\frac{{4{M_0}}}{L}\) |
| B. | \(\frac{{6{M_0}}}{L}\) |
| C. | \(\frac{{8{M_0}}}{L}\) |
| D. | \(\frac{{12{M_0}}}{L}\) |
| Answer» C. \(\frac{{8{M_0}}}{L}\) | |
| 25. |
A propped cantilever of span l is subjected to a concentrated load at mid-span. If Mp is the plastic moment capacity of the beam the value of collapse load will be |
| A. | \(\frac{{4{{\rm{M}}_{\rm{p}}}}}{{\rm{l}}}\) |
| B. | \(\frac{{6{{\rm{M}}_{\rm{p}}}}}{{\rm{l}}}\) |
| C. | \(\frac{{8{\rm{\;}}{{\rm{M}}_{\rm{p}}}}}{{\rm{l}}}\) |
| D. | \(\frac{{12{\rm{\;}}{{\rm{M}}_{\rm{p}}}}}{{\rm{l}}}\) |
| Answer» C. \(\frac{{8{\rm{\;}}{{\rm{M}}_{\rm{p}}}}}{{\rm{l}}}\) | |
| 26. |
A fixed-end beam is subjected to a concentrated load (P) as shown in the figure. The beam hastwo different segments having different plastic moment capacities (Mp, 2Mp) as shown.The minimum value of load (P)at which the beam would collapse (ultimate load) is |
| A. | 7.5 MP/L |
| B. | 5.0MP/L |
| C. | 4.5MP/L |
| D. | 2.5MP/L |
| Answer» B. 5.0MP/L | |
| 27. |
In regard to structural steel design and analysis, which of the following conditions should be satisfied in order to do elastic and plastic analysis? |
| A. | Yield condition |
| B. | Equilibrium condition |
| C. | Plastic moment condition |
| D. | Visco-elastic condition |
| Answer» C. Plastic moment condition | |
| 28. |
For a rectangular cross-section, when the extreme fibre strain was εy, the yield moment capacity is My. What would be the value of the resisting moment when the extreme fibre strain is 2εy? |
| A. | 1.000 My |
| B. | 1.250 My |
| C. | 1.375 My |
| D. | 1.550 My |
| Answer» D. 1.550 My | |
| 29. |
If the section shown in the figure turns from fully-elastic to fully-plastic, the depth of neutral axis (N.A), y̅, decreases by |
| A. | 13.75 mm |
| B. | 15.25 mm |
| C. | 10.75 mm |
| D. | 12.25 mm |
| Answer» B. 15.25 mm | |
| 30. |
A propped cantilever of span L carries a vertical concentrated load at the mid-span. If the plastic moment capacity of the section is Mp, the magnitude of the collapse load is: |
| A. | \(\frac{{8{M_p}}}{L}\) |
| B. | \(\frac{{6{M_p}}}{L}\) |
| C. | \(\frac{{4{M_p}}}{L}\) |
| D. | \(\frac{{2{M_p}}}{L}\) |
| Answer» C. \(\frac{{4{M_p}}}{L}\) | |
| 31. |
In the plastic analysis, the ratio of plastic moment MP to the yield moment MY is called |
| A. | Plastic hinge |
| B. | Shape factor |
| C. | Load factor |
| D. | Plastic strain |
| Answer» C. Load factor | |
| 32. |
For a fixed-end beam of length L and central point load of W, what will be the value of W at collapse?(Note: Plastic moment capacity of beam = Mp) |
| A. | 6 Mp / L |
| B. | 10 Mp / L |
| C. | 9 Mp / L |
| D. | 8 Mp / L |
| Answer» E. | |
| 33. |
In plastic method of analysis, the value of yield stress of the grade of steel shall not exceed. |
| A. | 250 MPa |
| B. | 415 MPa |
| C. | 450 MPa |
| D. | 500 MPa |
| Answer» D. 500 MPa | |
| 34. |
VIRTUAL_WORK_IS_USED_TO_DETERMINE______?$ |
| A. | yield load |
| B. | elastic load |
| C. | plastic load |
| D. | collapse load |
| Answer» E. | |
| 35. |
Principle of virtual work is used to satisfy ____? |
| A. | mechanism condition |
| B. | equilibrium condition |
| C. | plasticity condition |
| D. | no condition is satisfied |
| Answer» C. plasticity condition | |
| 36. |
What is principle of virtual work? |
| A. | work done by external forces is greater than work done by internal forces |
| B. | work done by external forces is less than work done by internal forces |
| C. | work done by external forces is equal to work done by internal forces |
| D. | work done by internal forces is greater than work done by external forces |
| Answer» D. work done by internal forces is greater than work done by external forces | |
| 37. |
Which load is obtained when equilibrium and mechanism conditions of plastic analysis are satisfied? |
| A. | plastic limit load |
| B. | upper bound solution of true ultimate load |
| C. | lower bound solution of true ultimate load |
| D. | no solution |
| Answer» C. lower bound solution of true ultimate load | |
| 38. |
Lowest plastic limit load is obtained when _____ |
| A. | only equilibrium condition of plastic analysis is satisfied |
| B. | only equilibrium and mechanism condition of plastic analysis are satisfied |
| C. | only mechanism condition of plastic analysis is satisfied |
| D. | equilibrium, mechanism and plasticity condition of plastic analysis are satisfied |
| Answer» E. | |
| 39. |
What is the condition for equilibrium in plastic analysis? |
| A. | bending moment distribution defined by assumed plastic hinges must not be in static equilibrium with applied loads and reactions |
| B. | shear force distribution defined by assumed plastic hinges must be in static equilibrium with applied loads and reactions |
| C. | bending moment distribution defined by assumed plastic hinges must be in static equilibrium with applied loads and reactions |
| D. | shear force distribution defined by assumed plastic hinges must not be in static equilibrium with applied loads and reactions |
| Answer» D. shear force distribution defined by assumed plastic hinges must not be in static equilibrium with applied loads and reactions | |