The analog signal m(t) is given below m(t) = 4 cos 100 pt + 8 sin 200 pt + cos 300 pt, the Nyquist sampling rate will be

The analog signal m(t) is given below m(t) = 4 cos 100 pt + 8 sin 200

1.	The analog signal m(t) is given below m(t) = 4 cos 100 pt + 8 sin 200 pt + cos 300 pt, the Nyquist sampling rate will be
A.	1/100
B.	1/200
C.	1/300
D.	1/600
Answer» D. 1/600