1.

Suppose r integers, 0 < r < 10, are chosen from (0, 1, 2, ...,9) at random and with replacement. The probability that no two are equal, is

A. \(\dfrac{10!}{10!r!}\)
B. \(\dfrac{10!}{10!(10-r)!}\)
C. \(\dfrac{10!}{r!(10-r)!}\)
D. \(\dfrac{10!}{10^r \times r! \times (10-r)!}\)
Answer» E.


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