1.

Solutions of the equation4x2 - 4a2x + (a4 - b4) = 0 are

A. \(\dfrac{a^2-b^2}{2},\dfrac{a^2+b^2}{2}\)
B. a + b, a - b
C. 2a2b + b2, 2ab
D. 0, 0
Answer» B. a + b, a - b


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