1.

Solution for the following differential equation with boundary conditions,y(0) = 2 and y(1) = -3 is \(\frac{{{d^2}y}}{{d{x^2}}} = 3x - 2\)

A. \(y = \frac{{{x^3}}}{3} - \frac{{{x^2}}}{2} + 3x - 6\)
B. \(y = 3{x^3} - \frac{{{x^2}}}{2} - 5x + 2\)
C. \(y = \frac{{{x^3}}}{2} - {x^2} - \frac{{9x}}{2} + 2\)
D. \(y = {x^3} - \frac{{{x^2}}}{2} + 5x + \frac{3}{2}\)
Answer» D. \(y = {x^3} - \frac{{{x^2}}}{2} + 5x + \frac{3}{2}\)


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