MCQOPTIONS
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| 1. |
Solution for the following differential equation with boundary conditions,y(0) = 2 and y(1) = -3 is \(\frac{{{d^2}y}}{{d{x^2}}} = 3x - 2\) |
| A. | \(y = \frac{{{x^3}}}{3} - \frac{{{x^2}}}{2} + 3x - 6\) |
| B. | \(y = 3{x^3} - \frac{{{x^2}}}{2} - 5x + 2\) |
| C. | \(y = \frac{{{x^3}}}{2} - {x^2} - \frac{{9x}}{2} + 2\) |
| D. | \(y = {x^3} - \frac{{{x^2}}}{2} + 5x + \frac{3}{2}\) |
| Answer» D. \(y = {x^3} - \frac{{{x^2}}}{2} + 5x + \frac{3}{2}\) | |