1.

\(\sin θ =-\dfrac{4}{5}\) and θ lies in the third quadrant, then \(\cos \dfrac{\theta}{2}\) is equal to:

A. \(\dfrac{1}{\sqrt{5}}\)
B. \(-\dfrac{1}{\sqrt{5}}\)
C. \(\sqrt{\dfrac{2}{5}}\)
D. \(-\sqrt{\dfrac{2}{5}}\)
Answer» C. \(\sqrt{\dfrac{2}{5}}\)


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