Reaction of LiAlH4 with one equivalent of Me3N∙HCl gives a tetrahedr – McqOptions

MCQOPTIONS

1.	Reaction of LiAlH4 with one equivalent of Me3N∙HCl gives a tetrahedral compound, which reacts with another equivalent of Me3N∙HCl to give compound N. The compound N and its geometry, respectively, are:
A.	LiAlH4NMe3 and trigonal bipyramidal
B.	Li2AlH4Cl and square pyramidal
C.	AlH3(NMe3)2 and trigonal bipyramidal
D.	AlH3(NMe3)2 and pentagonal bipyramidal
Answer» D. AlH3(NMe3)2 and pentagonal bipyramidal

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