Match the following list:List - IList – IIa) In half wave Rectifier dc voltage across load approximately for (rd ≪ RL)i) $\frac{{{V_m}}}{\pi }$b) Rectification efficiency of full wave rectifier in % isii) $\beta = \frac{1}{{29}}$c) Gain of amplifier in dBiii) $\frac{{81.2}}{{1 + \frac{{{r_d}}}{{{R_L}}}}}$d) Feedback factor when RC network is phase shift oscillator gives exactly 180° phase shiftiv) $20{\log _{10}}\frac{{{V_2}}}{{{V_1}}}$ Correct code are:

Question

Match the following list:List - IList – IIa) In half wave Rectifier dc voltage across load approximately for (rd ≪ RL)i) $\frac{{{V_m}}}{\pi }$b) Rectification efficiency of full wave rectifier in % isii) $\beta = \frac{1}{{29}}$c) Gain of amplifier in dBiii) $\frac{{81.2}}{{1 + \frac{{{r_d}}}{{{R_L}}}}}$d) Feedback factor when RC network is phase shift oscillator gives exactly 180° phase shiftiv) $20{\log _{10}}\frac{{{V_2}}}{{{V_1}}}$ Correct code are:

TuteeHUB · Accepted Answer

(a) – (iii), (b) – (ii), (c) – (iv), (d) – (i)

TuteeHUB · Answer

(a) – (ii), (b) – (i), (c) – (iii), (d) – (iv)

TuteeHUB · Answer

(a) – (i), (b) – (iii), (c) – (iv), (d) – (ii)

TuteeHUB · Answer

(a) – (iv), (b) – (iii), (c) – (ii), (d) – (i)

1.	Match the following list:List - IList – IIa) In half wave Rectifier dc voltage across load approximately for (rd ≪ RL)i) \(\frac{{{V_m}}}{\pi }\)b) Rectification efficiency of full wave rectifier in % isii) \(\beta = \frac{1}{{29}}\)c) Gain of amplifier in dBiii) \(\frac{{81.2}}{{1 + \frac{{{r_d}}}{{{R_L}}}}}\)d) Feedback factor when RC network is phase shift oscillator gives exactly 180° phase shiftiv) \(20{\log _{10}}\frac{{{V_2}}}{{{V_1}}}\) Correct code are:
A.	(a) – (ii), (b) – (i), (c) – (iii), (d) – (iv)
B.	(a) – (i), (b) – (iii), (c) – (iv), (d) – (ii)
C.	(a) – (iii), (b) – (ii), (c) – (iv), (d) – (i)
D.	(a) – (iv), (b) – (iii), (c) – (ii), (d) – (i)
Answer» C. (a) – (iii), (b) – (ii), (c) – (iv), (d) – (i)

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