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				| 1. | In the circuit shown below, the switch is closed at t = 0. Applied voltage is v (t) = 400cos (500t + π/4). Resistance R = 15Ω, inductance L = 0.2H and capacitance = 3 µF. Find the particular solution. | 
| A. | ip = 0.6cos(500t + π/4 + 88.5⁰) | 
| B. | ip = 0.6cos(500t + π/4 + 89.5⁰) | 
| C. | ip = 0.7cos(500t + π/4 + 89.5⁰) | 
| D. | ip = 0.7cos(500t + π/4 + 88.5⁰) | 
| Answer» E. | |