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				| 1. | In the circuit shown below, the switch is closed at t = 0. Applied voltage is v (t) = 400cos (500t + π/4). Resistance R = 15Ω, inductance L = 0.2H and capacitance = 3 µF. Find the complementary current. | 
| A. | ic = e-37.5t(c1cos1290t + c2sin1290t) | 
| B. | ic = e-37.5t(c1cos1290t – c2sin1290t) | 
| C. | ic = e37.5t(c1cos1290t – c2sin1290t) | 
| D. | ic = e37.5t(c1cos1290t + c2sin1290t) | 
| Answer» B. ic = e-37.5t(c1cos1290t – c2sin1290t) | |