In a klystron amplifier dc electron velocity is v0 and dc electron cha – McqOptions

MCQOPTIONS

1.	In a klystron amplifier dc electron velocity is v0 and dc electron charge density is r0 the dc beam current is
A.	r0v0
B.	r0/v0
C.	v0/r0
D.	(v0/r0)2
Answer» B. r0/v0

Discussion

No Comment Found

Related MCQs

Characteristic impedance of a coaxial cable is inversely proportional to ∈r.
Assertion (A): In rectangular waveguide TE01 mode is just TE10 mode rotated by 90°.Reason (R): When a rectangular waveguide is rotated by 90°, the broad and narrow dimensions get interchanged.
Consider the following applications SwitchAttenuatorPhase shifterOscillator In which of the above can a PIN diode be used?
In the given figure the equivalent circuit of a T attenuator. If the condition for matched attenuator is
A microstrip line has ∈r = 9. The normalised wavelength is about
A circular waveguide carries TE11 mode whole radial electric field is given byEr = E0j1(r) sin Φ V/mwhere r is radial distance in cm from the axisThe cut off wavelength is
Guide wavelength (λg), cutoff wavelength (λc) and free space wavelength (λ0) of a waveguide are related as
If ZTE is wave impedance for TE waves, Ed is maximum dielectric strength of insulating material, a and b are the width and height of a rectangular wave guide, the maximum power handling capability Pmax for TE10 mode is
If a and b are the width and height of rectangular wave-guide the cut off wavelength λc for TE20 mode is equal to
For a rectangular waveguide having width a and height b, the cutoff wavelength for TM11 mode is equal to