MCQOPTIONS
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| 1. |
If \[y=x\sin x,\]then |
| A. | \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{x}+\cot x\] |
| B. | \[\frac{dy}{dx}=\frac{1}{x}+\cot x\] |
| C. | \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{x}-\cot x\] |
| D. | None of these |
| Answer» B. \[\frac{dy}{dx}=\frac{1}{x}+\cot x\] | |