If \[x=\frac{3at}{1+{{t}^{3}}},y=\frac{3a{{t}^{2}}}{1+{{t}^{3}}},\]then \[\frac{dy}{dx}\]=

• A. \[\frac{t(2+{{t}^{3}})}{1-2{{t}^{3}}}\]
• B. \[\frac{t(2-{{t}^{3}})}{1-2{{t}^{3}}}\]
• C. \[\frac{t(2+{{t}^{3}})}{1+2{{t}^{3}}}\]
• D. \[\frac{t(2-{{t}^{3}})}{1+2{{t}^{3}}}\]