If \[x=a\sin \theta \] and \[y=b\]\[\cos \theta ,\] then \[\frac{{{d}^{2}}y}{d{{x}^{2}}}\] is [UPSEAT 2002]

\[\frac{-b}{{{a}^{2}}}{{\sec }^{3}}\theta \]

\[\frac{a}{{{b}^{2}}}{{\sec }^{2}}\theta \]

\[\frac{-b}{a}{{\sec }^{2}}\theta \]

\[\frac{-b}{{{a}^{2}}}{{\sec }^{3}}\theta \]

If \[x=a\sin \theta \] and \[y=b\]\[\cos \theta ,\] then \[\frac{{{d}^

1.	If \[x=a\sin \theta \] and \[y=b\]\[\cos \theta ,\] then \[\frac{{{d}^{2}}y}{d{{x}^{2}}}\] is [UPSEAT 2002]
A.	\[\frac{a}{{{b}^{2}}}{{\sec }^{2}}\theta \]
B.	\[\frac{-b}{a}{{\sec }^{2}}\theta \]
C.	\[\frac{-b}{{{a}^{2}}}{{\sec }^{3}}\theta \]
D.	\[\frac{-b}{{{a}^{2}}}{{\sec }^{3}}\theta \]
Answer» D. \[\frac{-b}{{{a}^{2}}}{{\sec }^{3}}\theta \]