MCQOPTIONS
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| 1. |
If \[y={{\sin }^{-1}}\sqrt{1-{{x}^{2}}}\], then \[dy/dx=\] [AISSE 1987] |
| A. | \[\frac{1}{\sqrt{1-{{x}^{2}}}}\] |
| B. | \[\frac{1}{\sqrt{1+{{x}^{2}}}}\] |
| C. | \[-\frac{1}{\sqrt{1-{{x}^{2}}}}\] |
| D. | \[-\frac{1}{\sqrt{{{x}^{2}}-1}}\] |
| Answer» D. \[-\frac{1}{\sqrt{{{x}^{2}}-1}}\] | |