1.

If x sin θ-y sinθ=√x²+y² and cos²θ/a²+sin²θ/b²=1/x²+y² then the correct relation is :

A. x²/a²+y²/b²=1
B. x²/b²+y²/a²=1
C. x²/a²-y²/b²=1
D. x²/b²-y²/a²=1
Answer» C. x²/a²-y²/b²=1


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