If the binary equivalent of 5.375 in normalized form is 0100 0000 1010 1100 0000 0000 0000 0000, what will be the output of the following program?#include <stdio.h>int main ( ){ float a =5.375 ; char *p ; int i ; p = (char *) &a ; for (i = 0 ; i <= 3 ; i++) printf("%02 X n" , (unsigned char) p[ i ]); return 0 ;}

If the binary equivalent of 5.375 in normalized form is 0100 0000 1010

1.	If the binary equivalent of 5.375 in normalized form is 0100 0000 1010 1100 0000 0000 0000 0000, what will be the output of the following program?#include <stdio.h>int main ( ){ float a =5.375 ; char p ; int i ; p = (char ) &a ; for (i = 0 ; i <= 3 ; i++) printf("%02 X n" , (unsigned char) p[ i ]); return 0 ;}
A.	40 AC 00 00
B.	04 CA 00 00
C.	00 00 AC 40
D.	00 00 CA 04
Answer» D. 00 00 CA 04

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If the binary equivalent of 5.375 in normalized form is 0100 0000 1010 1100 0000 0000 0000 0000, what will be the output of the following program?#include <stdio.h>int main ( ){ float a =5.375 ; char *p ; int i ; p = (char *) &a ; for (i = 0 ; i <= 3 ; i++) printf("%02 X n" , (unsigned char) p[ i ]); return 0 ;}
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