If R1 = 10k, R2 = 10k and capacitance = 10 μF the total time period o – McqOptions

MCQOPTIONS

1.	If R1 = 10k, R2 = 10k and capacitance = 10 μF the total time period of the astable multivibrator 555 is:
A.	0.207 s
B.	0.5 s
C.	0.138 s
D.	0.069 s
Answer» B. 0.5 s

Discussion

No Comment Found

Related MCQs

Pulsating output of a rectifier is converted into a steady DC level by
In any function where microphone, amplifier and speakers are used often one would hear a humming sound, which increases in volume gradually. This is due to:
Power dissipation and efficiency of series type switching regulator should follow which trend respectively?
Identify the main feature of power amplifiers from the options given below.
For an N bit F – V converter, to ensure less than ½ LSB output ripple, the time constant T of simple RC low pass filter must be at least (Where T0 is the output period of the n bit converter):
Most commonly used control element in voltage regulators is
Main element of a filter circuit that reduces the A.C. component of the output is
Directions: It consists of two statements, one labelled as the ‘Statement (I)’ and the other as ‘Statement (II)’. You are to examine these two statements carefully and select the answer using the codes given below:Statement (I): In push-pull operation one transistor conducts only for negative half cycle and other for positive half cycle.Statement (II): Class-B power amplifier is fixed in cut-off, which gives non-distorted output.
Low efficiency of a power amplifier results in
If a high degree of selectivity is desired, then double tuned circuit should have