If length of major axis is 10 and minor axis is 8 and major axis is along x-axis then find the equation of ellipse.

\((\frac{x}{10})^2+(\frac{y}{8})^2\)=1

\((\frac{x}{4})^2+(\frac{y}{5})^2\)=1

\((\frac{x}{5})^2+(\frac{y}{4})^2\)=1

\((\frac{x}{10})^2+(\frac{y}{8})^2\)=1

\((\frac{x}{8})^2+(\frac{y}{10})^2\)=1

If length of major axis is 10 and minor axis is 8 and major axis is a

1.	If length of major axis is 10 and minor axis is 8 and major axis is along x-axis then find the equation of ellipse.
A.	\((\frac{x}{4})^2+(\frac{y}{5})^2\)=1
B.	\((\frac{x}{5})^2+(\frac{y}{4})^2\)=1
C.	\((\frac{x}{10})^2+(\frac{y}{8})^2\)=1
D.	\((\frac{x}{8})^2+(\frac{y}{10})^2\)=1
Answer» C. \((\frac{x}{10})^2+(\frac{y}{8})^2\)=1

If foci of an ellipse are (0, ±3) and length of semimajor axis is 5 units, then find the equation of ellipse.
If length of major axis is 10 and minor axis is 8 and major axis is along x-axis then find the equation of ellipse.
What is equation of latus rectums of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
What is length of latus rectum for ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
What is minor axis length for ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
What is major axis length for ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
What is eccentricity for \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
Find the coordinates of foci of ellipse \((\frac{x}{16})^2+(\frac{y}{25})^2\)=1.
Find the coordinates of foci of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1.
The center of ellipse is same as a vertex.