Find the coordinates of foci of ellipse \((\frac{x}{16})^2+(\frac{y}{

1.	Find the coordinates of foci of ellipse \((\frac{x}{16})^2+(\frac{y}{25})^2\)=1.
A.	(±3,0)
B.	(±4,0)
C.	(0,±3)
D.	(0,±4)
Answer» D. (0,±4)

Discussion

If foci of an ellipse are (0, ±3) and length of semimajor axis is 5 units, then find the equation of ellipse.
If length of major axis is 10 and minor axis is 8 and major axis is along x-axis then find the equation of ellipse.
What is equation of latus rectums of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
What is length of latus rectum for ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
What is minor axis length for ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
What is major axis length for ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
What is eccentricity for \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
Find the coordinates of foci of ellipse \((\frac{x}{16})^2+(\frac{y}{25})^2\)=1.
Find the coordinates of foci of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1.
The center of ellipse is same as a vertex.