If integrating factor of x(1 - x2) dy + (2x2y - y - ax3) dx = 0 is \({e^{\int {Pdx} }}\), then P is equal to

\(\frac{{2{x^2} - a{x^3}}}{{x(1 - {x^2})}}\)

\(\frac{{2{x^2} - 1}}{{a{x^3}}}\)

\(\frac{{2{x^2} - 1}}{{x(1 - {x^2})}}\)

If integrating factor of x(1 - x2) dy + (2x2y - y - ax3) dx = 0 is \(

1.	If integrating factor of x(1 - x2) dy + (2x2y - y - ax3) dx = 0 is \({e^{\int {Pdx} }}\), then P is equal to
A.	\(\frac{{2{x^2} - a{x^3}}}{{x(1 - {x^2})}}\)
B.	2x3 - 1
C.	\(\frac{{2{x^2} - 1}}{{a{x^3}}}\)
D.	\(\frac{{2{x^2} - 1}}{{x(1 - {x^2})}}\)
Answer» E.

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