1.

General solution of the equation (x3 + 3xy2)dx + (3x2y + y3)dy = 0 is (c is a constant)

A. \(\frac{1}{4}\left( {{x^4} + 6{x^2}{y^2} + {y^4}} \right) = c\)
B. \(\frac{1}{5}\left( {8{x^4} + 6{x^3}y + {y^3}} \right) = c\)
C. \(\frac{1}{{12}}\left( {{x^3} + 6x{y^2} + {y^4}} \right) = c\)
D. (x2 + y2) = c
Answer» B. \(\frac{1}{5}\left( {8{x^4} + 6{x^3}y + {y^3}} \right) = c\)


Discussion

No Comment Found