For \(\frac{{{d^2}y}}{{d{x^2}}} + 4\frac{{dy}}{{dx}} + 3y = 3{e^{2x}}\), the particular integral is :

\({C_1}{e^{ - x}} + {C_2}{e^{ - 3x}}\)

For \(\frac{{{d^2}y}}{{d{x^2}}} + 4\frac{{dy}}{{dx}} + 3y = 3{e^{2x}}

1.	For \(\frac{{{d^2}y}}{{d{x^2}}} + 4\frac{{dy}}{{dx}} + 3y = 3{e^{2x}}\), the particular integral is :
A.	\(\frac{1}{{15}}{e^{2x}}\)
B.	\(\frac{1}{5}{e^{2x}}\)
C.	\(3{e^{2x}}\)
D.	\({C_1}{e^{ - x}} + {C_2}{e^{ - 3x}}\)
Answer» C. \(3{e^{2x}}\)

For \(\frac{{{d^2}y}}{{d{x^2}}} + 4\frac{{dy}}{{dx}} + 3y = 3{e^{2x}}\), the particular integral is :
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