If a^2 + b^2 =2 and c^2 +d^2 =1 then the value of (ad-bc)^2 + (ac+ bd) – McqOptions

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1.	If a^2 + b^2 =2 and c^2 +d^2 =1 then the value of (ad-bc)^2 + (ac+ bd)^2 will be -
A.	0
B.	1/2
C.	3/11
D.	2
Answer» E.

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