\[\frac{d}{dx}\left( {{\tan }^{-1}}\sqrt{\frac{1+\cos \frac{x}{2}}{1-\cos \frac{x}{2}}} \right)\]is equal to [MP PET 2004]

\[\frac{d}{dx}\left( {{\tan }^{-1}}\sqrt{\frac{1+\cos \frac{x}{2}}{1-\

1.	\[\frac{d}{dx}\left( {{\tan }^{-1}}\sqrt{\frac{1+\cos \frac{x}{2}}{1-\cos \frac{x}{2}}} \right)\]is equal to [MP PET 2004]
A.	\[-\frac{1}{4}\]
B.	\[\frac{1}{2}\]
C.	\[-\frac{1}{2}\]
D.	\[\frac{1}{4}\]
Answer» B. \[\frac{1}{2}\]