\[\frac{d}{dx}\left( {{\tan }^{-1}}\frac{\cos x}{1+\sin x} \right)=\] [AISSE 1984, 85; MNR 1983; RPET 1997]

\[\frac{d}{dx}\left( {{\tan }^{-1}}\frac{\cos x}{1+\sin x} \right)=\]

1.	\[\frac{d}{dx}\left( {{\tan }^{-1}}\frac{\cos x}{1+\sin x} \right)=\] [AISSE 1984, 85; MNR 1983; RPET 1997]
A.	\[-\frac{1}{2}\]
B.	\[\frac{1}{2}\]
C.	\[-1\]
D.	1
Answer» B. \[\frac{1}{2}\]