For what value of a & b for which the two surfaces ax2 byz = (a+2)x & 4x2y + z3 = 4 will be orthogonal to each other at the point (1,-1,2).

Question

For what value of a & b for which the two surfaces ax2   byz = (a+2)x & 4x2y + z3 = 4 will be orthogonal to each other at the point (1,-1,2).

TuteeHUB · Accepted Answer

(a =   frac{-3}{2}   ,   &   , b = -1   )

TuteeHUB · Answer

(a = 1   ,   &   , b =   frac{3}{2}   )

TuteeHUB · Answer

(a =   frac{-3}{2}   ,   &   , b = 1   )

TuteeHUB · Answer

(a =   frac{3}{2}   ,   &   , b = 1   )

TuteeHUB · Answer

(a =   frac{-3}{2}   ,   &   , b = -1   )

1.	For what value of a & b for which the two surfaces ax2 byz = (a+2)x & 4x2y + z3 = 4 will be orthogonal to each other at the point (1,-1,2).
A.	(a = 1 , & , b = frac{3}{2} )
B.	(a = frac{-3}{2} , & , b = 1 )
C.	(a = frac{3}{2} , & , b = 1 )
D.	(a = frac{-3}{2} , & , b = -1 )
Answer» D. (a = frac{-3}{2} , & , b = -1 )

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