Explore topic-wise MCQs in Linear Algebra.

This section includes 5 Mcqs, each offering curated multiple-choice questions to sharpen your Linear Algebra knowledge and support exam preparation. Choose a topic below to get started.

1.

Find the value of A3-3A2-28A, A = ( begin{bmatrix}-1&2&8 -2&3&0 -4&5&1 end{bmatrix} ).

A. ( begin{bmatrix}80&-126&-504 126&-172&-63 252&-316&-46 end{bmatrix} )
B. ( begin{bmatrix}80&-126&-504 126&-172&-63 252&-315&-46 end{bmatrix} )
C. ( begin{bmatrix}40&-126&-504 126&-172&-63 252&-315&-46 end{bmatrix} )
D. ( begin{bmatrix}40&-126&-504 126&-172&-63 252&-316&-46 end{bmatrix} )
Answer» C. ( begin{bmatrix}40&-126&-504 126&-172&-63 252&-315&-46 end{bmatrix} )
Discussion
2.

Find the value of 2A3+4A2, where = ( begin{bmatrix}5&0&-1 1&2&-1 -3&4&1 end{bmatrix} ).

A. ( begin{bmatrix}-200&0&-24 24&-32&-24 -72&96&-56 end{bmatrix} )
B. ( begin{bmatrix}-200&0&-24 24&-32&-12 -72&96&-56 end{bmatrix} )
C. ( begin{bmatrix}-200&0&-24 12&-32&-24 -72&96&-56 end{bmatrix} )
D. ( begin{bmatrix}-100&0&-12 12&-16&-12 -36&48&-28 end{bmatrix} )
Answer» B. ( begin{bmatrix}-200&0&-24 24&-32&-12 -72&96&-56 end{bmatrix} )
Discussion
3.

Find the value of A3+19A, A= ( begin{bmatrix}2&-3&1 2&0&-1 1&4&5 end{bmatrix} ).

A. ( begin{bmatrix}42&-14&70 21&+21&-21 105&119&203 end{bmatrix} )
B. ( begin{bmatrix}42&-7&70 21&-21&-21 105&119&203 end{bmatrix} )
C. ( begin{bmatrix}42&-14&70 21&-21&-21 105&119&203 end{bmatrix} )
D. ( begin{bmatrix}42&-7&70 21&+21&-21 105&119&203 end{bmatrix} )
Answer» D. ( begin{bmatrix}42&-7&70 21&+21&-21 105&119&203 end{bmatrix} )
Discussion
4.

Find the value of A3 where A= ( begin{bmatrix}-1&-1&2 0&1&-1 2&2&1 end{bmatrix} ).

A. ( begin{bmatrix}3&5&-1 -2&-9&2 -2&-4&-5 end{bmatrix} )
B. ( begin{bmatrix}3&5&-1 1&-9&1 -2&-4&-5 end{bmatrix} )
C. ( begin{bmatrix}3&5&-1 -2&-9&1 -2&-4&-5 end{bmatrix} )
D. ( begin{bmatrix}3&5&-1 -1&-9&1 -2&-4&-5 end{bmatrix} )
Answer» D. ( begin{bmatrix}3&5&-1 -1&-9&1 -2&-4&-5 end{bmatrix} )
Discussion
5.

Find the inverse of the given Matrix, using Cayley Hamilton s Theorem.A= ( begin{bmatrix}1&2&3 2&3&4 3&4&5 end{bmatrix} )

A. A<sup>-1</sup>= ( frac{1}{16} begin{bmatrix}2&amp;-3&amp;-1 4&amp;-2&amp;-6 -6&amp;9&amp;11 end{bmatrix} )
B. A<sup>-1</sup>= ( frac{1}{8} begin{bmatrix}2&amp;-3&amp;-1 4&amp;-2&amp;-3 -6&amp;9&amp;11 end{bmatrix} )
C. A<sup>-1</sup>= ( frac{1}{16} begin{bmatrix}2&amp;-1&amp;-1 4&amp;-2&amp;-6 -6&amp;9&amp;11 end{bmatrix} )
D. A<sup>-1</sup>= ( frac{1}{8} begin{bmatrix}2&amp;-3&amp;-1 4&amp;-2&amp;-6 -6&amp;9&amp;11 end{bmatrix} )
Answer» E.
Discussion