1.

For unrooted trees, the number of unrooted tree topologies (NU) is ________

A. NU = (2n− 5)!/2ⁿ⁻³(n− 5)!
B. NU = (2n− 5)!/2ⁿ⁻³(n− 3)!
C. NU = (2n− 5)!/2¯²(n− 3)!
D. NU = (2n− 5)!/2ⁿ(n− 3)!
Answer» C. NU = (2n− 5)!/2¯²(n− 3)!


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