

MCQOPTIONS
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1. |
For a given connected network and for a fixed tree, the fundamental loop matrix is given by\(B = \left[ \begin{matrix} 1 & 0 & 0 & 1 & 0 & 0 \\ 0 & 1 & 0 & 0 & 0 & -1 \\ 0 & 0 & 1 & 1 & -1 & -1 \\ \end{matrix} \right]\)The fundamental cut-set matrix Q corresponding to the same tree is given by |
A. | \(Q = \left[ \begin{matrix} -1 & 0 & -1 & 1 & 0 & 0 \\ 0 & 0 & 1 & 0 & 1 & 0 \\ 0 & 1 & 1 & 0 & 0 & 1 \\ \end{matrix} \right]\) |
B. | \(Q = \left[ \begin{matrix} -1 & 0 & 1 & 1 & 0 & 0 \\ 0 & 0 & -1 & 0 & 1 & 0 \\ 0 & 1 & 1 & 0 & 0 & 1 \\ \end{matrix} \right]\) |
C. | \(Q = \left[ \begin{matrix} 1 & 0 & 1 & 1 & 0 & 0 \\ 0 & 0 & -1 & 0 & 1 & 0 \\ 0 & 1 & 1 & 0 & 0 & 1 \\ \end{matrix} \right]\) |
D. | \(Q= \left[ \begin{matrix} 0 & 0 & 0 & 1 & 0 & 0 \\ 0 & 1 & 0 & 0 & 0 & -1 \\ 1 & 0 & 1 & 1 & -1 & -1 \\ \end{matrix} \right]\) |
Answer» B. \(Q = \left[ \begin{matrix} -1 & 0 & 1 & 1 & 0 & 0 \\ 0 & 0 & -1 & 0 & 1 & 0 \\ 0 & 1 & 1 & 0 & 0 & 1 \\ \end{matrix} \right]\) | |