Find the warping stress in the interior of the pavement for the data given below.Temperature differential, t = 17°CPoisson’s ratio, μ = 0.15Modulus of elasticity, E = 2×105 kg/cm2Thermal coefficient, e = 10×10-6 /°CCx=0.75 and Cy=0.56.

Find the warping stress in the interior of the pavement for the data

1.	Find the warping stress in the interior of the pavement for the data given below.Temperature differential, t = 17°CPoisson’s ratio, μ = 0.15Modulus of elasticity, E = 2×105 kg/cm2Thermal coefficient, e = 10×10-6 /°CCx=0.75 and Cy=0.56.
A.	15.5 kg/cm2
B.	14 kg/cm2
C.	15 kg/cm2
D.	14.5 kg/cm2
Answer» E.

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Find the warping stress in the interior of the pavement for the data given below.Temperature differential, t = 17°CPoisson’s ratio, μ = 0.15Modulus of elasticity, E = 2×105 kg/cm2Thermal coefficient, e = 10×10-6 /°CCx=0.75 and Cy=0.56.

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