

MCQOPTIONS
Saved Bookmarks
1. |
Find the warping stress at the corner of the pavement for the data given below.Pavement thickness = 25 cmRadius of relative stiffness = 64.50 cmTemperature differential = 0.6°C per cm of slab thicknessRadius of contact area = 15 cmPoisson’s ratio = 0.15Modulus of elasticity = 2.1×105 kg/cm2Thermal coefficient = 10×10-6/°C |
A. | 6.59 kg/cm2 |
B. | 5.96 kg/cm2 |
C. | 6.95 kg/cm2 |
D. | 5.69 kg/cm2 |
Answer» C. 6.95 kg/cm2 | |