Find the value of A3+19A, A=$\begin{bmatrix}2&-3&1\2&0&-1\1&4&5\end{bmatrix}$.

Question

TuteeHUB · Accepted Answer

$\begin{bmatrix}42&-7&70\21&+21&-21\105&119&203\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}42&-14&70\21&+21&-21\105&119&203\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}42&-7&70\21&-21&-21\105&119&203\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}42&-14&70\21&-21&-21\105&119&203\end{bmatrix}$

TuteeHUB · Answer

$\begin{bmatrix}42&-7&70\21&+21&-21\105&119&203\end{bmatrix}$

1.	Find the value of A3+19A, A=\(\begin{bmatrix}2&-3&1\\2&0&-1\\1&4&5\end{bmatrix}\).
A.	\(\begin{bmatrix}42&-14&70\\21&+21&-21\\105&119&203\end{bmatrix}\)
B.	\(\begin{bmatrix}42&-7&70\\21&-21&-21\\105&119&203\end{bmatrix}\)
C.	\(\begin{bmatrix}42&-14&70\\21&-21&-21\\105&119&203\end{bmatrix}\)
D.	\(\begin{bmatrix}42&-7&70\\21&+21&-21\\105&119&203\end{bmatrix}\)
Answer» D. \(\begin{bmatrix}42&-7&70\\21&+21&-21\\105&119&203\end{bmatrix}\)

Find the value of A3+19A, A=\(\begin{bmatrix}2&-3&1\\2&0&-1\\1&4&5\end{bmatrix}\).